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Biology * » Information *

Information *

How is information stored in the human brain or on the computer?

Energy concentrations expanding three-dimensionally can expand in two different ways: evenly or by pulsating rhythmically. The data stored on the computer is in the form of either 0 or 1, that is, the code contains only two kinds of characters.

Let us picture that the memories in our brain are stored in such a way that the three-dimensionally expanding energy concentrations expand rhythmically in some parts of the brain, and evenly in others. Now we have data stored, which can be retrieved if needed, and sometimes even when there is no need.

Sometimes a person who suffers from a concussion experiences memory blackouts for a while. You might assume that a concussion causes atoms within a certain area of the brain to release such dense energy waves that the data stored in that particular area cannot get through, which is why the person does not remember everything. In time, the expansion of the three-dimensionally expanding energy concentrations settles and finds a normal balance, and so information gets through again.

And what about computer data that is thrown in the “trash can”? Where does it go?

Mechanically speaking, it does not go anywhere. The rhythmic expansion of energy concentrations in a particular area can be turned into even expansion, causing the code to vanish, and new data may take the place of the deleted data.

For example, the heart expands rhythmically, and if it stops, the heart may be charged with one set of information, which is then stored in the three-dimensionally expanding energy concentrations in the heart. The energy concentrations keep the data stored and continue to pulsate and expand.


Addition: This needs to be thought over a little more. This topic gave me away; I don’t always do enough background work. I got into a conversation with my football pals about how data is stored. And I found out that the 0 sign is uncharged and the 1 sign has a low charge, perhaps 5, if I remember correctly. But as I said, this requires some more thought.